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Probability

Grade 5-7

Tree Diagrams

A tree diagram lays out every possible combination of two or more events as branches, and two simple rules unlock it: multiply along a branch to find one specific outcome, and add branches together when more than one outcome counts. This lesson covers multiplying along branches, finding a missing probability, adding across branches for combined outcomes, and tree diagrams for picking without replacement.

Asad, Co-Founder of Teachably

Written by Asad, Co-Founder of Teachably

Video walkthrough coming soon

The written lesson below covers everything you need in the meantime.

Multiplying along a branch

Each complete path through a tree diagram, from the start to one of the final outcomes, represents one specific combination of results. Multiply the probabilities along that single path to find the probability of that exact outcome.

A spinner with P(red) = 0.4 is spun twice. The probability of red then red is found by multiplying along that branch: 0.4 × 0.4 = 0.16.

Finding a missing probability

At any point where the branches split, the probabilities of all the branches from that point must add up to 1. Use this to find a missing probability by subtracting the known branches from 1.

A spinner has P(red) = 0.35, so P(blue) at the same point is 1 - 0.35 = 0.65.

Adding across branches for combined outcomes

When more than one path through the tree counts as a valid outcome, such as "exactly one" or "at least one", find the probability of each matching path separately by multiplying along it, then add these probabilities together.

A biased coin has P(heads) = 0.7 and is flipped twice. The probability of exactly one head comes from two paths, heads-then-tails and tails-then-heads: (0.7 × 0.3) + (0.3 × 0.7) = 0.21 + 0.21 = 0.42.

Tree diagrams without replacement

When an item is picked and not replaced, the total number of items left changes for the second pick, and so does the number of items matching each outcome if that outcome was picked first. The probabilities on the second set of branches depend on what happened on the first branch.

A bag has 5 red and 3 blue counters, 8 in total. After picking a red counter without replacing it, 4 red and 3 blue counters remain out of 7, so the second branch from "red" shows P(red) = 4/7 and P(blue) = 3/7.

Worked Examples

Three exam-style questions, fully solved.

A spinner can land on red or blue. P(red) = 0.35. The tree diagram shows the spinner spun twice. Find the missing probability of blue on the second spin, following a first spin of red.

Easy
  1. 1.Recognise that the branches from the same point must add up to 1
  2. 2.Subtract the known probability from 1: 1 - 0.35

Answer: 0.65

A bag contains 5 red and 3 blue counters. Two counters are picked at random, without replacement. Use the tree diagram to find the probability that both are red.

Medium
  1. 1.Find the probability of red on the first pick: 5/8
  2. 2.Find the probability of red on the second pick, given the first was red: 4/7, since one red counter has been removed
  3. 3.Multiply along the branch: 5/8 × 4/7

Answer: 5/14

A bag contains 4 red and 6 blue counters. Two counters are picked at random, without replacement. Use the tree diagram to find the probability of picking one red and one blue, in either order.

Hard
  1. 1.Find the probability of red then blue: 4/10 × 6/9 = 24/90
  2. 2.Find the probability of blue then red: 6/10 × 4/9 = 24/90
  3. 3.Add the two matching branches together: 24/90 + 24/90

Answer: 8/15

Avoid These

The most common mistakes students make.

01

Forgetting that the probabilities on branches from the same point must add up to 1 when finding a missing value.

02

Adding the probabilities along a single branch instead of multiplying them to find the probability of one specific path.

03

When a question needs "at least one" or "exactly one", only using one matching branch instead of adding together every branch that gives that outcome.

04

Using the same denominator for the second pick as the first pick when picking without replacement, instead of reducing it by one.

05

Forgetting that the numerator on the second branch also changes without replacement, depending on what was picked first.

FAQ

Questions parents and students ask.

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